Jan 15
Syntax highlighting for Django using Pygments
The wonderful django-mingus includes a few separate syntax highlighters, including one from django-sugar. However, the pygmentize template filter only works on <code> blocks and tries to guess the language.
A better syntax would be to include the language in the class of the code block, like so:
<code class="python">
import this
print [r for r in range(0,10,2)]
</code>
You can use this template filter, which is adapted from the Pygments Rendering Template Filter at Django Snippets.
import re
import pygments
from django import template
from pygments import lexers
from pygments import formatters
from BeautifulSoup import BeautifulSoup
register = template.Library()
regex = re.compile(r'<code(.*?)>(.*?)</code>', re.DOTALL)
@register.filter(name='pygmentize')
def pygmentize(value):
last_end = 0
to_return = ''
found = 0
for match_obj in regex.finditer(value):
code_class = match_obj.group(1)
code_string = match_obj.group(2)
if code_class.find('class'):
language = re.split(r'"|\'', code_class)[1]
lexer = lexers.get_lexer_by_name(language)
else:
try:
lexer = lexers.guess_lexer(str(code))
except ValueError:
lexer = lexers.PythonLexer()
pygmented_string = pygments.highlight(code_string, lexer, formatters.HtmlFormatter())
to_return = to_return + value[last_end:match_obj.start(0)] + pygmented_string
last_end = match_obj.end(2)
found = found + 1
to_return = to_return + value[last_end:]
return to_return
This is a template filter, which can be applied like so:
{{ code|pygmentize }}
You can read more about custom tempalte filters at the Django Project: Writing Custom Template Filters.
